What is the derivative of 0.04e^xx^2 ?

The derivative of 0.04e^xx^2 is 0.04(e^xx^2+2xe^x)

What is the first derivative of 0.04e^xx^2 ?

The first derivative of 0.04e^xx^2 is 0.04(e^xx^2+2xe^x)

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\frac{d}{d x} (0.04 e^{x} x^{2})

0.04 (e^{x} x^{2} + 2 x e^{x})

Solution steps

\frac{d}{d x} (0.04 e^{x} x^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 0.04 \frac{d}{d x} (e^{x} x^{2})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = e^{x}, g = x^{2}

= 0.04 (\frac{d}{d x} (e^{x}) x^{2} + \frac{d}{d x} (x^{2}) e^{x})

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (x^{2}) = 2 x

= 0.04 (e^{x} x^{2} + 2 x e^{x})

x \to 3 lim (j (x))

y^{^{'}} = \frac{cos ( 9 x )}{e ^{9 y}}

\frac{d}{d y} (3 x + x^{2} y)

f (x) = 6 sin (x), at x = \frac{π}{6}

20 x

What is the derivative of 0.04e^xx^2 ?
The derivative of 0.04e^xx^2 is 0.04(e^xx^2+2xe^x)
What is the first derivative of 0.04e^xx^2 ?
The first derivative of 0.04e^xx^2 is 0.04(e^xx^2+2xe^x)