What is the solution for (dy)/(dt)=t^2(1+15y) ?

The solution for (dy)/(dt)=t^2(1+15y) is y=(e^{5t^3+c_{1}})/(15)-1/15

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(dy)/(dt)=t^2(1+15y)

\frac{d y}{d t} = t^{2} (1 + 15 y)

y = \frac{e ^{5 t^{3} + c_{1}}}{15} - \frac{1}{15}

Solution steps

\frac{d y}{d t} = t^{2} (1 + 15 y)

Solve separable ODE:

y = \frac{e ^{5 t^{3} + c_{1}}}{15} - \frac{1}{15}

y = \frac{e ^{5 t^{3} + c_{1}}}{15} - \frac{1}{15}

\frac{\partial}{\partial x} (x^{2} sin (3 x - 2 y))

x \to a lim (g (x))

\int 3 x^{2} + 15 x - 11 d x

y^{^{''}} + y = t

\int \frac{sin ^{7} ( x )}{cos ^{4} ( x )} d x

What is the solution for (dy)/(dt)=t^2(1+15y) ?
The solution for (dy)/(dt)=t^2(1+15y) is y=(e^{5t^3+c_{1}})/(15)-1/15