What is the tangent of 2/(5x+3),\at x=-1 ?

The tangent of 2/(5x+3),\at x=-1 is y=-5/2 x-7/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of 2/(5x+3),\at x=-1

tangent of

\frac{2}{5 x + 3}, at x = - 1

y = - \frac{5}{2} x - \frac{7}{2}

Solution steps

Find the tangent point:

(- 1, - 1)

Find the slope of

y = \frac{2}{5 x + 3} : \frac{d y}{d x} = - \frac{10}{( 5 x + 3 ) ^{2}}

Compute the slope of

y = \frac{2}{5 x + 3}

x = - 1 : m = - \frac{5}{2}

Find the line with slope m=

- \frac{5}{2}

and passing through

(- 1, - 1) : y = - \frac{5}{2} x - \frac{7}{2}

y = - \frac{5}{2} x - \frac{7}{2}

\frac{d}{d x} (\frac{( x + 1 ) ( 2 x - 3 )}{2 x + 3})

\int cos^{3} (\frac{x}{9}) d x

\int sin^{4} (z)

f (x) = 4 x - 3 x^{2}, (2, - 4)

y = \frac{x}{1 - 5 x}

What is the tangent of 2/(5x+3),\at x=-1 ?
The tangent of 2/(5x+3),\at x=-1 is y=-5/2 x-7/2