What is the derivative of (x^2-49/(x-7)) ?

The derivative of (x^2-49/(x-7)) is 1

What is the first derivative of (x^2-49/(x-7)) ?

The first derivative of (x^2-49/(x-7)) is 1

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\frac{d}{d x} (\frac{x ^{2} - 49}{x - 7})

1

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 49}{x - 7})

Simplify

\frac{x ^{2} - 49}{x - 7} : x + 7

= \frac{d}{d x} (x + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (7)

\frac{d x}{d x} = 1

\frac{d}{d x} (7) = 0

= 1 + 0

Simplify

= 1

\int 2 + 2 sin (θ) d θ

x \to 0 lim (\frac{1}{x ^{2} - 1})

y^{^{'}} (x) = \frac{3 x ^{2}}{3 y ^{2} - 11}, y (1) = 0

x^{2} - 3 x + 3

\frac{d y}{d x} = 2 x + 3 y - 1

What is the derivative of (x^2-49/(x-7)) ?
The derivative of (x^2-49/(x-7)) is 1
What is the first derivative of (x^2-49/(x-7)) ?
The first derivative of (x^2-49/(x-7)) is 1