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Popular >

xxy^'=y^2+1

Solution

xx y^{^{'}} = y^{2} + 1

Solution

y = tan (- \frac{1}{x} + c_{1})

Solution steps

xx y^{'} (x) = y^{2} + 1

Solve separable ODE:

y = tan (- \frac{1}{x} + c_{1})

y = tan (- \frac{1}{x} + c_{1})

Popular Examples

5y^{''}+25y^'+1700y=0

5 y^{^{''}} + 25 y^{^{'}} + 1700 y = 0

derivative of y=arccos(3x)derivative of

y = arccos (3 x)

slope of (-5,-5),(5,5)slope

(- 5, - 5), (5, 5)

integral of 1/(x^2)sqrt(7+1/x)

\int \frac{1}{x ^{2}} 7 + \frac{1}{x} d x

derivative of x^4-5x

\frac{d}{d x} (x^{4} - 5 x)

Frequently Asked Questions (FAQ)

What is the solution for xxy^'=y^2+1 ?
The solution for xxy^'=y^2+1 is y=tan(-1/x+c_{1})