What is the tangent of f(x)=7x-6sqrt(x),(1,1) ?

The tangent of f(x)=7x-6sqrt(x),(1,1) is y=4x-3

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tangent of f(x)=7x-6sqrt(x),(1,1)

tangent of

f (x) = 7 x - 6 x, (1, 1)

y = 4 x - 3

Solution steps

Find the slope of

f (x) = 7 x - 6 x : \frac{df ( x )}{d x} = 7 - \frac{3}{x}

Compute the slope of

f (x) = 7 x - 6 x

(1, 1) : m = 4

Find the line with slope m=

4

and passing through

(1, 1) : y = 4 x - 3

y = 4 x - 3

y^{^{'''}} - y^{^{''}} + y^{^{'}} - y = x

\frac{\partial}{\partial x} (e^{x} \cdot sin (x))

8 y^{^{'}} = 3 e^{\frac{x}{8}} + y

\frac{d}{d x} (\frac{8 x}{3 - cot ( x )})

\int \frac{1}{e ^{2 x} - 2 e ^{x}} d x

What is the tangent of f(x)=7x-6sqrt(x),(1,1) ?
The tangent of f(x)=7x-6sqrt(x),(1,1) is y=4x-3