What is the derivative of f(x)=x^3-3x^2-9x+2 ?

The derivative of f(x)=x^3-3x^2-9x+2 is 3x^2-6x-9

What is the first derivative of f(x)=x^3-3x^2-9x+2 ?

The first derivative of f(x)=x^3-3x^2-9x+2 is 3x^2-6x-9

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derivative of

f (x) = x^{3} - 3 x^{2} - 9 x + 2

3 x^{2} - 6 x - 9

Solution steps

\frac{d}{d x} (x^{3} - 3 x^{2} - 9 x + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (9 x) + \frac{d}{d x} (2)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (9 x) = 9

\frac{d}{d x} (2) = 0

= 3 x^{2} - 6 x - 9 + 0

Simplify

= 3 x^{2} - 6 x - 9

\int_{1}^{b} \frac{1}{x ^{2}} d x

\int sin (x + 4) d x

y^{^{'}} + cos (x) y = 2 cos (x)

x \to - 1 - lim (x)

f (x) = 5 arcsin (x^{4})

What is the derivative of f(x)=x^3-3x^2-9x+2 ?
The derivative of f(x)=x^3-3x^2-9x+2 is 3x^2-6x-9
What is the first derivative of f(x)=x^3-3x^2-9x+2 ?
The first derivative of f(x)=x^3-3x^2-9x+2 is 3x^2-6x-9