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Popular >

x^'=2(x+1),x(0)=0

Solution

x^{^{'}} = 2 (x + 1), x (0) = 0

Solution

x = e^{2 t} - 1

Solution steps

x^{'} (t) = 2 (x + 1)

Solve separable ODE:

x = e^{2 t} - 1

x = e^{2 t} - 1

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Frequently Asked Questions (FAQ)

What is the solution for x^'=2(x+1),x(0)=0 ?
The solution for x^'=2(x+1),x(0)=0 is x=e^{2t}-1