What is the solution for (dy)/(dx)=(sqrt(y^2-9)) ?

The solution for (dy)/(dx)=(sqrt(y^2-9)) is y= 3/(2e^{x+c_{1)}}+(3e^{x+c_{1}})/2

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(dy)/(dx)=(sqrt(y^2-9))

\frac{d y}{d x} = (y^{2} - 9)

y = \frac{3}{2 e ^{x + c_{1}}} + \frac{3 e ^{x + c_{1}}}{2}

Solution steps

\frac{d y}{d x} = (y^{2} - 9)

Solve separable ODE:

y = \frac{3}{2 e ^{x + c_{1}}} + \frac{3 e ^{x + c_{1}}}{2}

y = \frac{3}{2 e ^{x + c_{1}}} + \frac{3 e ^{x + c_{1}}}{2}

\frac{\partial}{\partial x} (e^{- 5 t} cos (π x))

x \to - 1 lim (- 1)

\int 2 x (x^{2} + 13)^{7} d x

(6, 1), (4, 3)

f (x) = x^{2} cos^{2} (x at x) = - 2

What is the solution for (dy)/(dx)=(sqrt(y^2-9)) ?
The solution for (dy)/(dx)=(sqrt(y^2-9)) is y= 3/(2e^{x+c_{1)}}+(3e^{x+c_{1}})/2