What is the integral of 7/(3+7x^2) ?

The integral of 7/(3+7x^2) is sqrt(7/3)arctan(sqrt(7/3)x)+C

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integral of 7/(3+7x^2)

\int \frac{7}{3 + 7 x ^{2}} d x

\frac{7}{3} arctan (\frac{7}{3} x) + C

Solution steps

\int \frac{7}{3 + 7 x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 \cdot \int \frac{1}{3 + 7 x ^{2}} d x

Apply Integral Substitution

= 7 \cdot \int \frac{1}{21 ( 1 + u ^{2} )} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 \cdot \frac{1}{21} \cdot \int \frac{1}{1 + u ^{2}} d u

Use the common integral:

\int \frac{1}{1 + u ^{2}} d u = arctan (u)

= 7 \cdot \frac{1}{21} arctan (u)

Substitute back

u = \frac{7}{3} x

= 7 \cdot \frac{1}{21} arctan (\frac{7}{3} x)

Simplify

7 \cdot \frac{1}{21} arctan (\frac{7}{3} x) : \frac{7}{3} arctan (\frac{7}{3} x)

= \frac{7}{3} arctan (\frac{7}{3} x)

Add a constant to the solution

= \frac{7}{3} arctan (\frac{7}{3} x) + C

n = 2 \sum \infty n e^{- n}

f (x) = e^{4 a} (4 a^{3} - 3)

\frac{d}{d x} (ln (tan (x)))

\int 7 x^{2} x^{3} + 15 d x

\frac{d y}{d x} = 3 x + y

What is the integral of 7/(3+7x^2) ?
The integral of 7/(3+7x^2) is sqrt(7/3)arctan(sqrt(7/3)x)+C