What is the solution for x^2y^{''}-9xy^'+25y=0 ?

The solution for x^2y^{''}-9xy^'+25y=0 is y=c_{1}x^5+c_{2}ln(x)x^5

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x^2y^{''}-9xy^'+25y=0

x^{2} y^{^{''}} - 9 x y^{^{'}} + 25 y = 0

y = c_{1} x^{5} + c_{2} ln (x) x^{5}

Solution steps

x^{2} y^{''} (x) - 9 x y^{'} (x) + 25 y = 0

Solve linear ODE:

y = c_{1} x^{5} + c_{2} ln (x) x^{5}

y = c_{1} x^{5} + c_{2} ln (x) x^{5}

f (x) = 36 x^{- 2} - 2 x^{- 4} + 2

\frac{d}{d x} ((x + b)^{2})

a^{7} + cos^{7} (x)

\int_{3}^{4} (x^{3} - π x^{2}) d x

\frac{d}{d x} (\frac{- 7 x}{2 x - 1})

What is the solution for x^2y^{''}-9xy^'+25y=0 ?
The solution for x^2y^{''}-9xy^'+25y=0 is y=c_{1}x^5+c_{2}ln(x)x^5