What is the tangent of y=tan(x),\at x=-(7pi)/4 ?

The tangent of y=tan(x),\at x=-(7pi)/4 is y=2x+1+(7pi)/2

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tangent of y=tan(x),\at x=-(7pi)/4

tangent of

y = tan (x), at x = - \frac{7 π}{4}

y = 2 x + 1 + \frac{7 π}{2}

Solution steps

Find the tangent point:

(- \frac{7 π}{4}, 1)

Find the slope of

y = tan (x) : \frac{d y}{d x} = sec^{2} (x)

Compute the slope of

y = tan (x)

x = - \frac{7 π}{4} : m = 2

Find the line with slope m=

2

and passing through

(- \frac{7 π}{4}, 1) : y = 2 x + 1 + \frac{7 π}{2}

y = 2 x + 1 + \frac{7 π}{2}

\int \frac{cos ( x )}{3 + sin ( x )} d x

\frac{\partial}{\partial y} (4 (x - y) e^{4 y + 5 x^{2}})

x \to a lim ((f (x))^{g (x)})

\int sin (8 x) cos (2 x) d x

x^{^{''}} + 5 x = 0

What is the tangent of y=tan(x),\at x=-(7pi)/4 ?
The tangent of y=tan(x),\at x=-(7pi)/4 is y=2x+1+(7pi)/2