What is the d/(dθ)(6cos(θ)+8sin(θ)) ?

The d/(dθ)(6cos(θ)+8sin(θ)) is -6sin(θ)+8cos(θ)

What is the first d/(dθ)(6cos(θ)+8sin(θ)) ?

The first d/(dθ)(6cos(θ)+8sin(θ)) is -6sin(θ)+8cos(θ)

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\frac{d}{d θ} (6 cos (θ) + 8 sin (θ))

- 6 sin (θ) + 8 cos (θ)

Solution steps

\frac{d}{d θ} (6 cos (θ) + 8 sin (θ))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d θ} (6 cos (θ)) + \frac{d}{d θ} (8 sin (θ))

\frac{d}{d θ} (6 cos (θ)) = - 6 sin (θ)

\frac{d}{d θ} (8 sin (θ)) = 8 cos (θ)

= - 6 sin (θ) + 8 cos (θ)

\frac{d y}{d x} = \frac{( 2 x sec ( \frac{y}{x} ) + y )}{x}

\frac{d y}{d x} + \frac{8 y}{x + 2} = (x + 2)^{6}

\int_{0}^{3} 4 x d x

x \to - 1 lim (\frac{x ^{2} + x}{x + 1})

What is the d/(dθ)(6cos(θ)+8sin(θ)) ?
The d/(dθ)(6cos(θ)+8sin(θ)) is -6sin(θ)+8cos(θ)
What is the first d/(dθ)(6cos(θ)+8sin(θ)) ?
The first d/(dθ)(6cos(θ)+8sin(θ)) is -6sin(θ)+8cos(θ)