What is the integral of 1/((3-4x)) ?

The integral of 1/((3-4x)) is -1/4 ln|3-4x|+C

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integral of 1/((3-4x))

\int \frac{1}{( 3 - 4 x )} d x

- \frac{1}{4} ln ∣ 3 - 4 x ∣ + C

Solution steps

\int \frac{1}{3 - 4 x} d x

Apply u-substitution

: \int - \frac{1}{4 u} d u

= \int - \frac{1}{4 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{4} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= - \frac{1}{4} ln ∣ u ∣

Substitute back

u = 3 - 4 x

= - \frac{1}{4} ln ∣ 3 - 4 x ∣

Add a constant to the solution

= - \frac{1}{4} ln ∣ 3 - 4 x ∣ + C

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What is the integral of 1/((3-4x)) ?
The integral of 1/((3-4x)) is -1/4 ln|3-4x|+C