What is the derivative of 3x^2+6x+cos(x) ?

The derivative of 3x^2+6x+cos(x) is 6x+6-sin(x)

What is the first derivative of 3x^2+6x+cos(x) ?

The first derivative of 3x^2+6x+cos(x) is 6x+6-sin(x)

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\frac{d}{d x} (3 x^{2} + 6 x + cos (x))

6 x + 6 - sin (x)

Solution steps

\frac{d}{d x} (3 x^{2} + 6 x + cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (6 x) + \frac{d}{d x} (cos (x))

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (cos (x)) = - sin (x)

= 6 x + 6 - sin (x)

f (x) = \frac{7}{x}

x \to \infty lim (- 1 + \frac{1}{x})

y^{^{'}} = tan (x) (sec (x))^{4}

n = 1 \sum \infty 7^{n + 1}

\int x^{3} e^{7 x} d x

What is the derivative of 3x^2+6x+cos(x) ?
The derivative of 3x^2+6x+cos(x) is 6x+6-sin(x)
What is the first derivative of 3x^2+6x+cos(x) ?
The first derivative of 3x^2+6x+cos(x) is 6x+6-sin(x)