What is the derivative of x^7ln(3x) ?

The derivative of x^7ln(3x) is 7x^6ln(3x)+x^6

What is the first derivative of x^7ln(3x) ?

The first derivative of x^7ln(3x) is 7x^6ln(3x)+x^6

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\frac{d}{d x} (x^{7} ln (3 x))

7 x^{6} ln (3 x) + x^{6}

Solution steps

\frac{d}{d x} (x^{7} ln (3 x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{7}, g = ln (3 x)

= \frac{d}{d x} (x^{7}) ln (3 x) + \frac{d}{d x} (ln (3 x)) x^{7}

\frac{d}{d x} (x^{7}) = 7 x^{6}

\frac{d}{d x} (ln (3 x)) = \frac{1}{x}

= 7 x^{6} ln (3 x) + \frac{1}{x} x^{7}

\frac{1}{x} x^{7} = x^{6}

= 7 x^{6} ln (3 x) + x^{6}

\int_{1}^{2} 5 r^{2} ln (r) d r

\frac{d}{d x} ((- 3 cos (2 x) - sin (3 x))^{2})

\frac{4 x}{9 - cot ( x )}

t \to 0 lim (e^{- 4 t})

\int \frac{( ln ( x ) ) ^{17}}{x} d x

What is the derivative of x^7ln(3x) ?
The derivative of x^7ln(3x) is 7x^6ln(3x)+x^6
What is the first derivative of x^7ln(3x) ?
The first derivative of x^7ln(3x) is 7x^6ln(3x)+x^6