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Popular >

y^'=x^2-1

Solution

y^{^{'}} = x^{2} - 1

Solution

y = \frac{x ^{3}}{3} - x + c_{1}

Solution steps

y^{'} (x) = x^{2} - 1

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int x^{2} - 1 d x

\int x^{2} - 1 d x = \frac{x ^{3}}{3} - x + c_{1}

y = \frac{x ^{3}}{3} - x + c_{1}

Popular Examples

limit as x approaches-pi of e^{tan(x)}

x \to - π lim (e^{t a n (x)})

area f(x)=-x^2+3x-1,-3,1 area

f (x) = - x^{2} + 3 x - 1, - 3, 1

y^{''}-y^'-2y=-4e^{3t}

y^{^{''}} - y^{^{'}} - 2 y = - 4 e^{3 t}

derivative of ((ax+b)/(cx+d))

\frac{d}{d x} (\frac{( a x + b )}{c x + d})

taylor 1/(x-1),11 taylor

\frac{1}{x - 1}, 11

Frequently Asked Questions (FAQ)

What is the solution for y^'=x^2-1 ?
The solution for y^'=x^2-1 is y=(x^3)/3-x+c_{1}