What is the integral from-1 to 1 of \sqrt[3]{t}-2 ?

The integral from-1 to 1 of \sqrt[3]{t}-2 is -4

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integral from-1 to 1 of \sqrt[3]{t}-2

- 4

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int_{- 1}^{1} 2 d t = 4

= 0 - 4

Simplify

= - 4

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What is the integral from-1 to 1 of \sqrt[3]{t}-2 ?
The integral from-1 to 1 of \sqrt[3]{t}-2 is -4