What is the integral from-2 to 3 of (x-4|x|) ?

The integral from-2 to 3 of (x-4|x|) is -47/2

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integral from-2 to 3 of (x-4|x|)

\int_{- 2}^{3} (x - 4 ∣ x ∣) d x

- \frac{47}{2}

Decimal Notation

- 23.5

Solution steps

\int_{- 2}^{3} x - 4 ∣ x ∣ d x

Eliminate Absolutes

= \int_{- 2}^{0} x - 4 (- x) d x + \int_{0}^{3} x - 4 x d x

\int_{- 2}^{0} x - 4 (- x) d x = - 10

\int_{0}^{3} x - 4 x d x = - \frac{27}{2}

= - 10 - \frac{27}{2}

Simplify

- 10 - \frac{27}{2} : - \frac{47}{2}

= - \frac{47}{2}

\int ((tan^{3} (x)) (sec^{4} (x))) d x

\frac{\partial}{\partial x} (3 x^{2} - 3 y^{2})

x \to - 4 lim (- 5 x)

\frac{d}{d x} (2 x 1 - x^{2})

x^{2} y^{^{''}} - 5 x y^{^{'}} + 8 y = 0

What is the integral from-2 to 3 of (x-4|x|) ?
The integral from-2 to 3 of (x-4|x|) is -47/2