What is the limit as n approaches infinity+of 1+1/n ?

The limit as n approaches infinity+of 1+1/n is 1

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limit as n approaches infinity+of 1+1/n

n \to \infty + lim (1 + \frac{1}{n})

1

Solution steps

n \to \infty lim (1 + \frac{1}{n})

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= n \to \infty lim (1) + n \to \infty lim (\frac{1}{n})

n \to \infty lim (1) = 1

n \to \infty lim (\frac{1}{n}) = 0

= 1 + 0

Simplify

= 1

\frac{\partial}{\partial y} (\frac{y e ^{x}}{x e ^{y}})

\int \frac{x ^{2}}{x ^{2} - 9} d x

\frac{d}{d x} (- 4^{3})

y = arccos (\frac{9}{x})

f (x) = 4 x - x^{2}

What is the limit as n approaches infinity+of 1+1/n ?
The limit as n approaches infinity+of 1+1/n is 1