What is the derivative of 8sin^2(x) ?

The derivative of 8sin^2(x) is 8sin(2x)

What is the first derivative of 8sin^2(x) ?

The first derivative of 8sin^2(x) is 8sin(2x)

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\frac{d}{d x} (8 sin^{2} (x))

8 sin (2 x)

Solution steps

\frac{d}{d x} (8 sin^{2} (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (sin^{2} (x))

Apply the chain rule:

2 sin (x) \frac{d}{d x} (sin (x))

= 2 sin (x) \frac{d}{d x} (sin (x))

\frac{d}{d x} (sin (x)) = cos (x)

= 8 \cdot 2 sin (x) cos (x)

Simplify

8 \cdot 2 sin (x) cos (x) : 8 sin (2 x)

= 8 sin (2 x)

\frac{d x}{d t} = 0.6 - \frac{3}{500} x

\int (4 + x^{7})^{3} 7 x^{6} d x

5 x^{2} cos (3 x)

y^{^{''}} - \frac{7}{t} y^{^{'}} + \frac{32}{t ^{2}} y = 0

x^{2} \cdot y^{^{'}} - 4 x y = sin (3 x) \cdot x^{6}

What is the derivative of 8sin^2(x) ?
The derivative of 8sin^2(x) is 8sin(2x)
What is the first derivative of 8sin^2(x) ?
The first derivative of 8sin^2(x) is 8sin(2x)