What is the derivative of b/(x^2) ?

The derivative of b/(x^2) is -(2b)/(x^3)

What is the first derivative of b/(x^2) ?

The first derivative of b/(x^2) is -(2b)/(x^3)

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\frac{d}{d x} (\frac{b}{x ^{2}})

- \frac{2 b}{x ^{3}}

Solution steps

\frac{d}{d x} (\frac{b}{x ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= b \frac{d}{d x} (\frac{1}{x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= b \frac{d}{d x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= b (- 2 x^{- 2 - 1})

Simplify

b (- 2 x^{- 2 - 1}) : - \frac{2 b}{x ^{3}}

= - \frac{2 b}{x ^{3}}

x \to 2 lim (\frac{( 3 x + 2 )}{5 x - 2})^{\frac{( 3 )}{x - 2}}

\int (x - 2) 2 d x

x \to \infty lim (x^{6} e^{- x^{5}})

\int sinh (1 + 4 x) d x

\frac{d}{d x} (a (2 x e^{2 x} + e^{2 x} \cdot 2 x^{2}))

What is the derivative of b/(x^2) ?
The derivative of b/(x^2) is -(2b)/(x^3)
What is the first derivative of b/(x^2) ?
The first derivative of b/(x^2) is -(2b)/(x^3)