What is (\partial)/(\partial x)((x+z-y)^2) ?

The answer to (\partial)/(\partial x)((x+z-y)^2) is 2(x+z-y)

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(\partial)/(\partial x)((x+z-y)^2)

\frac{\partial}{\partial x} ((x + z - y)^{2})

2 (x + z - y)

Solution steps

\frac{\partial}{\partial x} ((x + z - y)^{2})

Treat

z, y

as constants

Apply the chain rule:

2 (x + z - y) \frac{\partial}{\partial x} (x + z - y)

= 2 (x + z - y) \frac{\partial}{\partial x} (x + z - y)

\frac{\partial}{\partial x} (x + z - y) = 1

= 2 (x + z - y) \cdot 1

Simplify

= 2 (x + z - y)

(t^{2} + \frac{1}{2})^{2}

(x^{2} + 2 y^{2}) d x - x y d y = 0

\frac{\partial}{\partial x} (x e^{\frac{s}{x}})

\int \frac{( 4 x ^{2} + 2 )}{( x ^{2} - 2 x + 2 ) ^{2}} d x

\frac{d}{d x} (g (x) (x)^{2})

What is (\partial)/(\partial x)((x+z-y)^2) ?
The answer to (\partial)/(\partial x)((x+z-y)^2) is 2(x+z-y)