What is (\partial)/(\partial x)(sin(x^2+2y)) ?

The answer to (\partial)/(\partial x)(sin(x^2+2y)) is cos(x^2+2y)*2x

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(\partial)/(\partial x)(sin(x^2+2y))

\frac{\partial}{\partial x} (sin (x^{2} + 2 y))

cos (x^{2} + 2 y) \cdot 2 x

Solution steps

\frac{\partial}{\partial x} (sin (x^{2} + 2 y))

Treat

y

as a constant

Apply the chain rule:

cos (x^{2} + 2 y) \frac{\partial}{\partial x} (x^{2} + 2 y)

= cos (x^{2} + 2 y) \frac{\partial}{\partial x} (x^{2} + 2 y)

\frac{\partial}{\partial x} (x^{2} + 2 y) = 2 x

= cos (x^{2} + 2 y) \cdot 2 x

\int_{- \frac{π}{2}}^{\frac{π}{2}} cos (x) d x

\int \frac{22}{22 + e ^{x}} d x

f (x) = 9 - x^{2}, (3, 0)

\frac{d}{d y} (y \cdot e^{x \cdot y})

y^{^{'}} = y + t

What is (\partial)/(\partial x)(sin(x^2+2y)) ?
The answer to (\partial)/(\partial x)(sin(x^2+2y)) is cos(x^2+2y)*2x