What is the derivative of f(x)=4x^2-3x ?

The derivative of f(x)=4x^2-3x is 8x-3

What is the first derivative of f(x)=4x^2-3x ?

The first derivative of f(x)=4x^2-3x is 8x-3

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derivative of

f (x) = 4 x^{2} - 3 x

8 x - 3

Solution steps

\frac{d}{d x} (4 x^{2} - 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{2}) - \frac{d}{d x} (3 x)

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (3 x) = 3

= 8 x - 3

6 t e^{- t}

f (x) = \frac{1}{5 ( 4 )}

\frac{d}{d x} (\frac{e ^{2 - x} - 2 x}{e ^{2 - x} + 3 x})

\int x^{2} e^{13 x} d x

x \to 8 lim (\frac{1}{( x - 8 )})

What is the derivative of f(x)=4x^2-3x ?
The derivative of f(x)=4x^2-3x is 8x-3
What is the first derivative of f(x)=4x^2-3x ?
The first derivative of f(x)=4x^2-3x is 8x-3