What is the limit as x approaches 0+of xe^{2/x} ?

The limit as x approaches 0+of xe^{2/x} is infinity

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limit as x approaches 0+of xe^{2/x}

x \to 0 + lim (x e^{\frac{2}{x}})

\infty

Solution steps

x \to 0 + lim (x e^{\frac{2}{x}})

Rewrite for L'Hopital

= x \to 0 + lim (\frac{e ^{\frac{2}{x}}}{\frac{1}{x}})

Apply L'Hopital's Rule

: x \to 0 + lim \frac{- \frac{2 e ^{\frac{2}{x}}}{x ^{2}}}{- \frac{1}{x ^{2}}}

= x \to 0 + lim \frac{- \frac{2 e ^{\frac{2}{x}}}{x ^{2}}}{- \frac{1}{x ^{2}}}

Simplify

\frac{- \frac{2 e ^{\frac{2}{x}}}{x ^{2}}}{- \frac{1}{x ^{2}}} : 2 e^{\frac{2}{x}}

= x \to 0 + lim (2 e^{\frac{2}{x}})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= 2 \cdot x \to 0 + lim (e^{\frac{2}{x}})

Apply the Limit Chain Rule:

\infty

= 2 \cdot \infty

Apply Infinity Property:

c \cdot \infty = \infty

= \infty

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What is the limit as x approaches 0+of xe^{2/x} ?
The limit as x approaches 0+of xe^{2/x} is infinity