What is area |2x|,2x^2+x-4 ?

The answer to area |2x|,2x^2+x-4 is (28-7sqrt(41)-15sqrt(33))/(48)+4+sqrt(41)+sqrt(33)

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area |2x|,2x^2+x-4

area

∣ 2 x ∣, 2 x^{2} + x - 4

\frac{28 - 7 41 - 15 33}{48} + 4 + 41 + 33

Decimal Notation

14.00205 \dots

Solution steps

Apply the area formula:

\int_{\frac{- 3 - 41}{4}}^{\frac{1 + 33}{4}} 2 ∣ x ∣ - (2 x^{2} + x - 4) d x

Solve

\int_{\frac{- 3 - 41}{4}}^{\frac{1 + 33}{4}} 2 ∣ x ∣ - (2 x^{2} + x - 4) d x : \frac{28 - 7 41 - 15 33}{48} + 4 + 41 + 33

The area is:

= \frac{28 - 7 41 - 15 33}{48} + 4 + 41 + 33

x \to \infty lim (\frac{4 x + 2}{2 x - 7})

n = 0 \sum \infty \frac{1}{n + 10}

n = 1 \sum \infty (2 n + 1)^{- 9}

y^{^{''}} - 6 y^{^{'}} + 18 y = 0

\frac{d}{d x} (x^{3} - 2 x y + 3)

What is area |2x|,2x^2+x-4 ?
The answer to area |2x|,2x^2+x-4 is (28-7sqrt(41)-15sqrt(33))/(48)+4+sqrt(41)+sqrt(33)