What is the derivative of sqrt(1+x) ?

The derivative of sqrt(1+x) is 1/(2sqrt(1+x))

What is the first derivative of sqrt(1+x) ?

The first derivative of sqrt(1+x) is 1/(2sqrt(1+x))

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derivative of

1 + x

\frac{1}{2 1 + x}

Solution steps

\frac{d}{d x} (1 + x)

Apply the chain rule:

\frac{1}{2 1 + x} \frac{d}{d x} (1 + x)

= \frac{1}{2 1 + x} \frac{d}{d x} (1 + x)

\frac{d}{d x} (1 + x) = 1

= \frac{1}{2 1 + x} \cdot 1

Simplify

= \frac{1}{2 1 + x}

\frac{\partial}{\partial z} (z e^{x yz})

\frac{\partial}{\partial y} (\frac{y}{x - y})

\frac{\partial}{\partial y} ((x + y)^{3} - 12 x y)

\int x \cdot sin (2 x^{2}) d x

x \to 0 + lim (x^{2} e^{\frac{1}{x}})

What is the derivative of sqrt(1+x) ?
The derivative of sqrt(1+x) is 1/(2sqrt(1+x))
What is the first derivative of sqrt(1+x) ?
The first derivative of sqrt(1+x) is 1/(2sqrt(1+x))