What is the tangent of y=(|x|)/(sqrt(5-x^2)),(2,2) ?

The tangent of y=(|x|)/(sqrt(5-x^2)),(2,2) is y=5x-8

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tangent of y=(|x|)/(sqrt(5-x^2)),(2,2)

tangent of

y = \frac{∣ x ∣}{5 - x ^{2}}, (2, 2)

y = 5 x - 8

Solution steps

Find the slope of

y = \frac{∣ x ∣}{5 - x ^{2}} : \frac{d y}{d x} = \frac{5 x}{∣ x ∣ ( 5 - x ^{2} ) - x ^{2} + 5}

Compute the slope of

y = \frac{∣ x ∣}{5 - x ^{2}}

(2, 2) : m = 5

Find the line with slope m=

5

and passing through

(2, 2) : y = 5 x - 8

y = 5 x - 8

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What is the tangent of y=(|x|)/(sqrt(5-x^2)),(2,2) ?
The tangent of y=(|x|)/(sqrt(5-x^2)),(2,2) is y=5x-8