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Popular >

y^'+e^xy=2e^x

Solution

y^{^{'}} + e^{x} y = 2 e^{x}

Solution

y = - e^{- e^{x} - c_{1}} + 2

Solution steps

y^{'} (x) + e^{x} y = 2 e^{x}

Solve separable ODE:

y = - e^{- e^{x} - c_{1}} + 2

y = - e^{- e^{x} - c_{1}} + 2

Popular Examples

(dy)/(dx)+y=xye^{-4x}

\frac{d y}{d x} + y = x y e^{- 4 x}

integral of sin(θ)e^{cos(θ)}

\int sin (θ) e^{c o s (θ)} d θ

integral from 1 to 3 of sqrt(x)

\int_{1}^{3} x d x

integral of e^{2x}cos(4x)

\int e^{2 x} cos (4 x) d x

derivative of (ln(x)^{-2})

\frac{d}{d x} ((ln (x))^{- 2})

Frequently Asked Questions (FAQ)

What is the solution for y^'+e^xy=2e^x ?
The solution for y^'+e^xy=2e^x is y=-e^{-e^x-c_{1}}+2