What is the derivative of y=3x^2+1/x ?

The derivative of y=3x^2+1/x is 6x-1/(x^2)

What is the first derivative of y=3x^2+1/x ?

The first derivative of y=3x^2+1/x is 6x-1/(x^2)

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derivative of

y = 3 x^{2} + \frac{1}{x}

6 x - \frac{1}{x ^{2}}

Solution steps

\frac{d}{d x} (3 x^{2} + \frac{1}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (\frac{1}{x})

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

= 6 x - \frac{1}{x ^{2}}

\int x^{e} d x

\int \frac{2}{e ^{x} 11 + e ^{2 x}} d x

\int 7 cos^{3} (3 x) d x

x y^{^{'}} + 3 y = 0

x \to 0 + lim (3)

What is the derivative of y=3x^2+1/x ?
The derivative of y=3x^2+1/x is 6x-1/(x^2)
What is the first derivative of y=3x^2+1/x ?
The first derivative of y=3x^2+1/x is 6x-1/(x^2)