What is the sum from n=1 to infinity of 7^nx^{n-1} ?

The sum from n=1 to infinity of 7^nx^{n-1} is Radius of convergence is 1/7

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sum from n=1 to infinity of 7^nx^{n-1}

n = 1 \sum \infty 7^{n} x^{n - 1}

Radius of convergence is \frac{1}{7}

Solution steps

n = 1 \sum \infty 7^{n} x^{n - 1}

Use the Ratio Test to compute the convergence interval

Radius of convergence is \frac{1}{7}

y^{^{''}} + 6 y^{^{'}} + 8 y = cos (3 t), y (0) = - 2, y^{^{'}} (0) = 1

\int_{6}^{8} \frac{86}{( x - 6 ) ^{3}} d x

\frac{\partial}{\partial x} (2 x^{4} y^{2} + 3 x^{2} y^{4})

\int \frac{cos ( e ^{- x} )}{e ^{2 x}} d x

k = 1 \sum \infty \frac{4 k}{7 k - 1}

What is the sum from n=1 to infinity of 7^nx^{n-1} ?
The sum from n=1 to infinity of 7^nx^{n-1} is Radius of convergence is 1/7