What is the solution for (dy}{dx}=\frac{y(ln(y)-ln(x)+1))/x ?

The solution for (dy}{dx}=\frac{y(ln(y)-ln(x)+1))/x is y=e^{c_{1}x}x

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(dy}{dx}=\frac{y(ln(y)-ln(x)+1))/x

\frac{d y}{d x} = \frac{y ( ln ( y ) - ln ( x ) + 1 )}{x}

y = e^{c_{1} x} x

Solution steps

\frac{d y}{d x} = \frac{y ( ln ( y ) - ln ( x ) + 1 )}{x}

Solve using substitution:

y = e^{c_{1} x} x

y = e^{c_{1} x} x

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What is the solution for (dy}{dx}=\frac{y(ln(y)-ln(x)+1))/x ?
The solution for (dy}{dx}=\frac{y(ln(y)-ln(x)+1))/x is y=e^{c_{1}x}x