What is the tangent of f(x)=x^2,(-4,15) ?

The tangent of f(x)=x^2,(-4,15) is y=-6x-9 \lor y=-10x-25

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tangent of f(x)=x^2,(-4,15)

tangent of

f (x) = x^{2}, (- 4, 15)

y = - 6 x - 9 or y = - 10 x - 25

Solution steps

Slope of the tangent line at

(- 4, 15) : m = \frac{x ^{2} - 15}{x + 4}

Find the slope of

f (x) = x^{2} : m = 2 x

Solve

2 x = \frac{x ^{2} - 15}{x + 4} : x = - 3, x = - 5

Find the tangent line at

x = - 3 : y = - 6 x - 9

Find the tangent line at

x = - 5 : y = - 10 x - 25

y = - 6 x - 9 or y = - 10 x - 25

(8 x^{2} - 16 x + 16) e^{x}

x \to 1 lim (ln (e^{x} - 1))

\frac{d}{d x} (\frac{( x + 2 )}{( x + 1 )})

\int (1 - e^{- x}) d x

\frac{d ^{2} y}{d x ^{2}} - 3 \frac{d y}{d x} + 2 y = 10 sin (x)

What is the tangent of f(x)=x^2,(-4,15) ?
The tangent of f(x)=x^2,(-4,15) is y=-6x-9 \lor y=-10x-25