What is the integral from-1 to 1 of x(1-x^2) ?

The integral from-1 to 1 of x(1-x^2) is 0

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integral from-1 to 1 of x(1-x^2)

\int_{- 1}^{1} x (1 - x^{2}) d x

0

Solution steps

\int_{- 1}^{1} x (1 - x^{2}) d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

x (1 - x^{2}) :

Odd

= 0

\int sin^{2} (x) cos (n x) d x

\frac{d}{d x} (\frac{cos ( x )}{2 x})

f (x) = 9 - 3 x + 2 x^{2}, at x = - 6

\frac{d}{d x} (2 x - 3 x^{\frac{2}{3}})

\int 25 e^{- 2 x} d x

What is the integral from-1 to 1 of x(1-x^2) ?
The integral from-1 to 1 of x(1-x^2) is 0