What is the derivative of 49+23sin((2pi)/(52)(t-10)) ?

The derivative of 49+23sin((2pi)/(52)(t-10)) is (23pi)/(26)cos((pi(t-10))/(26))

What is the first derivative of 49+23sin((2pi)/(52)(t-10)) ?

The first derivative of 49+23sin((2pi)/(52)(t-10)) is (23pi)/(26)cos((pi(t-10))/(26))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

49 + 23 sin (\frac{2 π}{52} (t - 10))

\frac{23 π}{26} cos (\frac{π ( t - 10 )}{26})

Solution steps

\frac{d}{d t} (49 + 23 sin (\frac{2 π}{52} (t - 10)))

Simplify

49 + 23 sin (\frac{2 π}{52} (t - 10)) : 49 + 23 sin (\frac{π ( t - 10 )}{26})

= \frac{d}{d t} (49 + 23 sin (\frac{π ( t - 10 )}{26}))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (49) + \frac{d}{d t} (23 sin (\frac{π ( t - 10 )}{26}))

\frac{d}{d t} (49) = 0

\frac{d}{d t} (23 sin (\frac{π ( t - 10 )}{26})) = \frac{23 π}{26} cos (\frac{π ( t - 10 )}{26})

= 0 + \frac{23 π}{26} cos (\frac{π ( t - 10 )}{26})

Simplify

= \frac{23 π}{26} cos (\frac{π ( t - 10 )}{26})

\int \frac{1}{x 1 - ln ( x ^{2} )} d x

y^{^{'}} = \frac{2 x}{y}

\int 4 x - 6 d x

\int \frac{8 x - 3}{12 x ^{2} - 7 x + 1} d x

\int \frac{x ^{3}}{x ^{4} + 4} d x

What is the derivative of 49+23sin((2pi)/(52)(t-10)) ?
The derivative of 49+23sin((2pi)/(52)(t-10)) is (23pi)/(26)cos((pi(t-10))/(26))
What is the first derivative of 49+23sin((2pi)/(52)(t-10)) ?
The first derivative of 49+23sin((2pi)/(52)(t-10)) is (23pi)/(26)cos((pi(t-10))/(26))