What is the integral from 0 to 3 of (2e^x) ?

The integral from 0 to 3 of (2e^x) is 2(e^3-1)

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integral from 0 to 3 of (2e^x)

\int_{0}^{3} (2 e^{x}) d x

2 (e^{3} - 1)

Decimal Notation

38.17107 \dots

Solution steps

\int_{0}^{3} 2 e^{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{3} e^{x} d x

Use the common integral:

\int e^{x} d x = e^{x}

= 2 [e^{x}]_{0}^{3}

Compute the boundaries:

e^{3} - 1

= 2 (e^{3} - 1)

f (x) = \frac{x + 2}{10 - 3 x}

\int_{5}^{7} x^{3} d x

\int \frac{1 + e ^{- 2 x}}{e ^{x}} d x

\int_{0}^{3} 3 x^{2} d x

\frac{\partial}{\partial x} (x^{\frac{2}{5}} \cdot y^{\frac{3}{5}})

What is the integral from 0 to 3 of (2e^x) ?
The integral from 0 to 3 of (2e^x) is 2(e^3-1)