What is the tangent of y=sqrt(5x-2),(5,sqrt(23)) ?

The tangent of y=sqrt(5x-2),(5,sqrt(23)) is y= 5/(2sqrt(23))x+sqrt(23)-(25)/(2sqrt(23))

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tangent of y=sqrt(5x-2),(5,sqrt(23))

tangent of

y = 5 x - 2, (5, 23)

y = \frac{5}{2 23} x + 23 - \frac{25}{2 23}

Solution steps

Find the slope of

y = 5 x - 2 : \frac{d y}{d x} = \frac{5}{2 5 x - 2}

Compute the slope of

y = 5 x - 2

(5, 23) : m = \frac{5}{2 23}

Find the line with slope m=

\frac{5}{2 23}

and passing through

(5, 23) : y = \frac{5}{2 23} x + 23 - \frac{25}{2 23}

y = \frac{5}{2 23} x + 23 - \frac{25}{2 23}

at + b

y = x^{2} - 2 x

x \to 2 lim (e^{x - 5})

\int e^{1 - 2 x} d x

\frac{\partial}{\partial x} (e^{x e^{x}})

What is the tangent of y=sqrt(5x-2),(5,sqrt(23)) ?
The tangent of y=sqrt(5x-2),(5,sqrt(23)) is y= 5/(2sqrt(23))x+sqrt(23)-(25)/(2sqrt(23))