What is the integral from 1 to infinity of (1/(x^2)) ?

The integral from 1 to infinity of (1/(x^2)) is 1

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integral from 1 to infinity of (1/(x^2))

\int_{1}^{\infty} (\frac{1}{x ^{2}}) d x

1

Solution steps

\int_{1}^{\infty} \frac{1}{x ^{2}} d x

Compute the indefinite integral:

\int \frac{1}{x ^{2}} d x = - \frac{1}{x} + C

Compute the boundaries:

\int_{1}^{\infty} (\frac{1}{x ^{2}}) d x = 0 - (- 1)

= 0 - (- 1)

Simplify

= 1

x \to \infty lim (f (x) (x)^{2})

x \to - \infty lim (x^{2} - 1)

(x^{2} + 1) (x^{2} - 2 x)

f (x) = \frac{cos ( x )}{1 - sin ( x )}

\int \frac{1}{x} + sec^{2} (x) d x

What is the integral from 1 to infinity of (1/(x^2)) ?
The integral from 1 to infinity of (1/(x^2)) is 1