What is the tangent of y=(sqrt(x))/(x+1),(4,0.4) ?

The tangent of y=(sqrt(x))/(x+1),(4,0.4) is y=-3/100 x+0.52

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tangent of y=(sqrt(x))/(x+1),(4,0.4)

tangent of

y = \frac{x}{x + 1}, (4, 0.4)

y = - \frac{3}{100} x + 0.52

Solution steps

Find the slope of

y = \frac{x}{x + 1} : \frac{d y}{d x} = \frac{- x + 1}{2 x ( x + 1 ) ^{2}}

Compute the slope of

y = \frac{x}{x + 1}

(4, 0.4) : m = - \frac{3}{100}

Find the line with slope m=

- \frac{3}{100}

and passing through

(4, 0.4) : y = - \frac{3}{100} x + 0.52

y = - \frac{3}{100} x + 0.52

y^{^{''}} + 4 y = 5 csc^{2} (2 t)

\frac{\partial}{\partial z} (y sin (z))

\frac{tan ( x ) - 5}{sec ( x )}

\int sin (3 y) d y

f (x) = \frac{4}{x ^{4}} + 10 x

What is the tangent of y=(sqrt(x))/(x+1),(4,0.4) ?
The tangent of y=(sqrt(x))/(x+1),(4,0.4) is y=-3/100 x+0.52