What is (\partial)/(\partial z)(ysin(z)) ?

The answer to (\partial)/(\partial z)(ysin(z)) is ycos(z)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial z)(ysin(z))

\frac{\partial}{\partial z} (y sin (z))

y cos (z)

Solution steps

\frac{\partial}{\partial z} (y sin (z))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y \frac{\partial}{\partial z} (sin (z))

Apply the common derivative:

\frac{\partial}{\partial z} (sin (z)) = cos (z)

= y cos (z)

\frac{tan ( x ) - 5}{sec ( x )}

\int sin (3 y) d y

f (x) = \frac{4}{x ^{4}} + 10 x

\int t^{2} e^{- \frac{t}{4}} d t

\int_{- \infty}^{- 1} e^{- 18 t} d t

What is (\partial)/(\partial z)(ysin(z)) ?
The answer to (\partial)/(\partial z)(ysin(z)) is ycos(z)