What is (\partial)/(\partial x)(3x^2y^2+3) ?

The answer to (\partial)/(\partial x)(3x^2y^2+3) is 6xy^2

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(\partial)/(\partial x)(3x^2y^2+3)

\frac{\partial}{\partial x} (3 x^{2} y^{2} + 3)

6 x y^{2}

Solution steps

\frac{\partial}{\partial x} (3 x^{2} y^{2} + 3)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x^{2} y^{2}) + \frac{\partial}{\partial x} (3)

\frac{\partial}{\partial x} (3 x^{2} y^{2}) = 6 y^{2} x

\frac{\partial}{\partial x} (3) = 0

= 6 y^{2} x + 0

Simplify

= 6 x y^{2}

\int \frac{x}{( x ^{2} - 1 ) ^{\frac{3}{2}}} d x

\frac{d}{d x} (\frac{1}{e ^{- 2 x}})

\frac{( e ^{x} - e ^{- x} )}{2}

\int π cos (π) x d x

\int (x^{5} - 6 x) d x

What is (\partial)/(\partial x)(3x^2y^2+3) ?
The answer to (\partial)/(\partial x)(3x^2y^2+3) is 6xy^2