What is the derivative of f(x)=\sqrt[8]{x} ?

The derivative of f(x)=\sqrt[8]{x} is 1/(8x^{7/8)}

What is the first derivative of f(x)=\sqrt[8]{x} ?

The first derivative of f(x)=\sqrt[8]{x} is 1/(8x^{7/8)}

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derivative of

\frac{1}{8 x ^{\frac{7}{8}}}

Solution steps

Apply radical rule:

= \frac{d}{d x} (x^{\frac{1}{8}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{8} x^{\frac{1}{8} - 1}

Simplify

\frac{1}{8} x^{\frac{1}{8} - 1} : \frac{1}{8 x ^{\frac{7}{8}}}

= \frac{1}{8 x ^{\frac{7}{8}}}

\frac{d}{d x} (- 5 e^{- 5 x})

f (x) = \frac{1}{x ^{6}}, (1, 1)

\frac{d}{d x} (\frac{1}{4 x ^{3}} - \frac{5}{2 x})

\frac{\partial}{\partial x} (x^{2} + (y - 1)^{2} + z^{2})

x, x^{2.42}, [0.99, 1]

What is the derivative of f(x)=\sqrt[8]{x} ?
The derivative of f(x)=\sqrt[8]{x} is 1/(8x^{7/8)}
What is the first derivative of f(x)=\sqrt[8]{x} ?
The first derivative of f(x)=\sqrt[8]{x} is 1/(8x^{7/8)}