What is area cos(x),sin(x),[0, pi/2 ] ?

The answer to area cos(x),sin(x),[0, pi/2 ] is 2sqrt(2)-2

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area cos(x),sin(x),[0, pi/2 ]

area

cos (x), sin (x), [0, \frac{π}{2}]

22 - 2

Solution steps

Apply the area formula:

\int_{0}^{\frac{π}{2}} ∣ cos (x) - sin (x) ∣ d x

Solve

\int_{0}^{\frac{π}{2}} ∣ cos (x) - sin (x) ∣ d x : 22 - 2

The area is:

= 22 - 2

\int x^{5} 9 x^{2} - 1 d x

\frac{\partial}{\partial y} (3 x^{2} y + cos (y))

t y^{^{'}} + y t = 1 - y

\int_{0}^{π} sec^{2} (\frac{x}{4}) d x

\frac{\partial}{\partial x} (x^{2} + 8 x y + 3 y^{2})

What is area cos(x),sin(x),[0, pi/2 ] ?
The answer to area cos(x),sin(x),[0, pi/2 ] is 2sqrt(2)-2