What is (\partial)/(\partial x)(4x-y^2-4) ?

The answer to (\partial)/(\partial x)(4x-y^2-4) is 4

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(\partial)/(\partial x)(4x-y^2-4)

\frac{\partial}{\partial x} (4 x - y^{2} - 4)

4

Solution steps

\frac{\partial}{\partial x} (4 x - y^{2} - 4)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (4 x) - \frac{\partial}{\partial x} (y^{2}) - \frac{\partial}{\partial x} (4)

\frac{\partial}{\partial x} (4 x) = 4

\frac{\partial}{\partial x} (y^{2}) = 0

\frac{\partial}{\partial x} (4) = 0

= 4 - 0 - 0

Simplify

= 4

\int e^{- x} \cdot sin (x) d x

\int 9 tan^{3} (θ) d θ

x \to 2 lim (4 x^{2} + 5 x + 3)

\int \frac{1}{x 6 + 4 x} d x

f (x) = x^{2} (2 x + 9)^{3}

What is (\partial)/(\partial x)(4x-y^2-4) ?
The answer to (\partial)/(\partial x)(4x-y^2-4) is 4