What is the derivative of 1+sqrt(t) ?

The derivative of 1+sqrt(t) is 1/(2sqrt(t))

What is the first derivative of 1+sqrt(t) ?

The first derivative of 1+sqrt(t) is 1/(2sqrt(t))

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derivative of

1 + t

\frac{1}{2 t}

Solution steps

\frac{d}{d t} (1 + t)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (1) + \frac{d}{d t} (t)

\frac{d}{d t} (1) = 0

\frac{d}{d t} (t) = \frac{1}{2 t}

= 0 + \frac{1}{2 t}

Simplify

= \frac{1}{2 t}

x \to 0 + lim (x^{2 \cdot x})

\int_{1}^{\infty} \frac{1}{x + x x} d x

ln (\frac{e ^{x} + 1}{e ^{x} - 1})

\int_{1}^{2} \frac{1}{( 3 - 5 x ) ^{2}} d x

π^{x^{2}}

What is the derivative of 1+sqrt(t) ?
The derivative of 1+sqrt(t) is 1/(2sqrt(t))
What is the first derivative of 1+sqrt(t) ?
The first derivative of 1+sqrt(t) is 1/(2sqrt(t))