What is the tangent of x^4,\at x=-1/3 ?

The tangent of x^4,\at x=-1/3 is y=-4/27 x-1/27

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tangent of x^4,\at x=-1/3

tangent of

x^{4}, at x = - \frac{1}{3}

y = - \frac{4}{27} x - \frac{1}{27}

Solution steps

Find the tangent point:

(- \frac{1}{3}, \frac{1}{81})

Find the slope of

y = x^{4} : \frac{d y}{d x} = 4 x^{3}

Compute the slope of

y = x^{4}

x = - \frac{1}{3} : m = - \frac{4}{27}

Find the line with slope m=

- \frac{4}{27}

and passing through

(- \frac{1}{3}, \frac{1}{81}) : y = - \frac{4}{27} x - \frac{1}{27}

y = - \frac{4}{27} x - \frac{1}{27}

\int_{0}^{1} 3 e^{- 3 t} d t

\frac{\partial}{\partial x} (lo g_{13} (1 + x^{2}))

\frac{d}{d x} ((3 x + 1)^{\frac{1}{2}})

\frac{d}{d x} ((x^{2} - 3 x + 2) (2 x^{3} + 1))

\frac{d}{d x} (cos ((π x)^{8}))

What is the tangent of x^4,\at x=-1/3 ?
The tangent of x^4,\at x=-1/3 is y=-4/27 x-1/27