What is the (sqrt(9-x^2))^' ?

The (sqrt(9-x^2))^' is -x/(sqrt(9-x^2))

What is the first (sqrt(9-x^2))^' ?

The first (sqrt(9-x^2))^' is -x/(sqrt(9-x^2))

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(9 - x^{2})^{^{'}}

- \frac{x}{9 - x ^{2}}

Solution steps

(9 - x^{2})^{'}

Apply the chain rule:

\frac{1}{2 9 - x ^{2}} (9 - x^{2})^{'}

= \frac{1}{2 9 - x ^{2}} (9 - x^{2})^{'}

(9 - x^{2})^{'} = - 2 x

= \frac{1}{2 9 - x ^{2}} (- 2 x)

Simplify

\frac{1}{2 9 - x ^{2}} (- 2 x) : - \frac{x}{9 - x ^{2}}

= - \frac{x}{9 - x ^{2}}

f (x) = x e^{x^{2}}

\frac{d}{d x} (240 (1 - \frac{3}{3 + e ^{- 0.5 x}}))

e^{\frac{3}{2}}

\int x^{3} 3 + x^{4} d x

\frac{d}{d x} (5 sin (9 x))

What is the (sqrt(9-x^2))^' ?
The (sqrt(9-x^2))^' is -x/(sqrt(9-x^2))
What is the first (sqrt(9-x^2))^' ?
The first (sqrt(9-x^2))^' is -x/(sqrt(9-x^2))