What is the tangent of y= 3/x ,(4, 3/4) ?

The tangent of y= 3/x ,(4, 3/4) is y=-3/16 x+3/2

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tangent of y= 3/x ,(4, 3/4)

tangent of

y = \frac{3}{x}, (4, \frac{3}{4})

y = - \frac{3}{16} x + \frac{3}{2}

Solution steps

Find the slope of

y = \frac{3}{x} : \frac{d y}{d x} = - \frac{3}{x ^{2}}

Compute the slope of

y = \frac{3}{x}

(4, \frac{3}{4}) : m = - \frac{3}{16}

Find the line with slope m=

- \frac{3}{16}

and passing through

(4, \frac{3}{4}) : y = - \frac{3}{16} x + \frac{3}{2}

y = - \frac{3}{16} x + \frac{3}{2}

\int \frac{( 2 x + 1 )}{x - 1} d x

y^{^{''}} + 3 y^{^{'}} - 18 y = 0

\frac{d}{d x} (\frac{2 sin ( x )}{3 + cos ( x )})

y = 96 x^{2} + 72 x + 12

y^{^{'}} cos (x) = y sin (x) + sin (103 x)

What is the tangent of y= 3/x ,(4, 3/4) ?
The tangent of y= 3/x ,(4, 3/4) is y=-3/16 x+3/2