What is the derivative of (2(x+8(x-6))/(x^2-7^2)) ?

The derivative of (2(x+8(x-6))/(x^2-7^2)) is (2(-2x^2-2x-98))/((x^2-49)^2)

What is the first derivative of (2(x+8(x-6))/(x^2-7^2)) ?

The first derivative of (2(x+8(x-6))/(x^2-7^2)) is (2(-2x^2-2x-98))/((x^2-49)^2)

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\frac{d}{d x} (\frac{2 ( x + 8 ) ( x - 6 )}{x ^{2} - 7 ^{2}})

\frac{2 ( - 2 x ^{2} - 2 x - 98 )}{( x ^{2} - 49 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{2 ( x + 8 ) ( x - 6 )}{x ^{2} - 7 ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{( x + 8 ) ( x - 6 )}{x ^{2} - 7 ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 2 \cdot \frac{\frac{d}{d x} ( ( x + 8 ) ( x - 6 ) ) ( x ^{2} - 7 ^{2} ) - \frac{d}{d x} ( x ^{2} - 7 ^{2} ) ( x + 8 ) ( x - 6 )}{( x ^{2} - 7 ^{2} ) ^{2}}

\frac{d}{d x} ((x + 8) (x - 6)) = 2 x + 2

\frac{d}{d x} (x^{2} - 7^{2}) = 2 x

= 2 \cdot \frac{( 2 x + 2 ) ( x ^{2} - 7 ^{2} ) - 2 x ( x + 8 ) ( x - 6 )}{( x ^{2} - 7 ^{2} ) ^{2}}

Simplify

2 \cdot \frac{( 2 x + 2 ) ( x ^{2} - 7 ^{2} ) - 2 x ( x + 8 ) ( x - 6 )}{( x ^{2} - 7 ^{2} ) ^{2}} : \frac{2 ( - 2 x ^{2} - 2 x - 98 )}{( x ^{2} - 49 ) ^{2}}

= \frac{2 ( - 2 x ^{2} - 2 x - 98 )}{( x ^{2} - 49 ) ^{2}}

\frac{d}{d x} ((\frac{2 x + 4}{3 x - 1})^{4})

\int \frac{5 sin ( x )}{x} d x

y^{^{'}} - \frac{2}{t} y = t^{3}

\int 20 + 75 e^{- \frac{t}{50}} d t

t \cdot cos (π \cdot t)

What is the derivative of (2(x+8(x-6))/(x^2-7^2)) ?
The derivative of (2(x+8(x-6))/(x^2-7^2)) is (2(-2x^2-2x-98))/((x^2-49)^2)
What is the first derivative of (2(x+8(x-6))/(x^2-7^2)) ?
The first derivative of (2(x+8(x-6))/(x^2-7^2)) is (2(-2x^2-2x-98))/((x^2-49)^2)